{"id":17116,"date":"2024-05-06T22:26:03","date_gmt":"2024-05-06T22:26:03","guid":{"rendered":"http:\/\/dudoanlode3mien.com\/?p=17116"},"modified":"2024-05-06T22:26:03","modified_gmt":"2024-05-06T22:26:03","slug":"hoc-lom-cao-nhan-du-doan-xo-chinh-xac","status":"publish","type":"post","link":"https:\/\/dudoanlode3mien.com\/hoc-lom-cao-nhan-du-doan-xo-chinh-xac\/","title":{"rendered":"H\u1ecdc l\u1ecfm cao nh\u00e2n d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 ch\u00ednh x\u00e1c"},"content":{"rendered":"

\u1eaet h\u1eb3n nhi\u1ec1u ng\u01b0\u1eddi lu\u00f4n \u0111au \u0111\u1ea7u suy ngh\u0129 v\u00e0 khao kh\u00e1t t\u00ecm \u0111\u01b0\u1ee3c c\u00e1ch soi c\u1ea7u chu\u1ea9n<\/strong>. B\u00e0i vi\u1ebft n\u00e0y ch\u00fang t\u00f4i xin gi\u1edbi thi\u1ec7u t\u1edbi anh em c\u00e1ch d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1<\/strong> c\u1ee7a c\u00e1c cao nh\u00e2n si\u00eau ch\u00ednh x\u00e1c. C\u00e1c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u01b0\u1ee3c d\u1ef1a v\u00e0o c\u00e1c c\u00e1ch t\u00ednh khoa h\u1ecdc c\u00f3 \u0111\u1ed9 tin c\u1eady cao.<\/p>\n

Ph\u01b0\u01a1ng ph\u00e1p d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 theo c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t<\/h2>\n

\u0110\u1ec3 d\u1ef1 \u0111o\u00e1n \u0111\u01b0\u1ee3c con s\u1ed1 s\u1ebd ra ng\u00e0y h\u00f4m nay, c\u00e1c b\u1ea1n c\u00f3 th\u1ec3 t\u00ednh x\u00e1c su\u1ea5t c\u1ee7a t\u1eebng con s\u1ed1. T\u1eeb \u0111\u00f3 r\u00fat ra con s\u1ed1 n\u00e0o c\u00f3 t\u1ec9 l\u1ec7 v\u1ec1 cao nh\u1ea5t \u0111\u1ec3 \u0111\u00e1nh. C\u00e1ch ch\u01a1i n\u00e0y h\u01a1i m\u1ea5t th\u1eddi gian nh\u01b0ng n\u00f3 th\u1ef1c s\u1ef1 \u0111\u00e3 \u0111em l\u1ea1i hi\u1ec7u qu\u1ea3 cho ng\u01b0\u1eddi ch\u01a1i.<\/p>\n

C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang 1 con l\u00f4<\/h3>\n

Ph\u01b0\u01a1ng ph\u00e1p d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1<\/strong> n\u00e0y ch\u1ec9 t\u00ednh x\u00e1c su\u1ea5t tr\u00fang duy nh\u1ea5t 1 con l\u00f4 kh\u00f4ng t\u00ednh tr\u01b0\u1eddng h\u1ee3p tr\u00fang 2 s\u1ed1, hay 3 s\u1ed1.
\nC\u00f4ng th\u1ee9c: 1 \u2013 0,99^27 = 23,7657%
\nTrong \u0111\u00f3 0,99^27 l\u00e0 x\u00e1c su\u1ea5t tr\u01b0\u1ee3t c\u1ea3 27 con.<\/p>\n

\"du-doan-xo-so-8\"
H\u1ecdc l\u1ecfm cao nh\u00e2n d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 ch\u00ednh x\u00e1c<\/figcaption><\/figure>\n

C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang 1 con \u0111\u1ec1<\/h3>\n

\u0110\u1ec1 ch\u1ec9 c\u00f3 m\u1ed9t gi\u1ea3i duy nh\u1ea5t, mu\u1ed1n tr\u00fang \u0111\u1ec1 b\u1ea1n ph\u1ea3i t\u00ecm ra c\u1eb7p s\u1ed1 t\u1eeb 00 – 99 nh\u01b0 v\u1eady hi\u1ec3n nhi\u00ean x\u00e1c su\u1ea5t tr\u00fang \u0111\u1ec1 l\u00e0 1%.<\/p>\n

C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2<\/a><\/h3>\n

\u0110\u1ec3 tr\u00fang l\u00f4 xi\u00ean 2 b\u1eaft bu\u1ed9c b\u1ea1n ph\u1ea3i \u0111\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 \u0111\u00fang c\u1ea3 2 con s\u1ed1. N\u1ebfu nh\u01b0 b\u1ea1n ch\u1ec9 d\u1ef1 \u0111o\u00e1n tr\u00fang 1 trong 2 ho\u1eb7c kh\u00f4ng \u0111o\u00e1n tr\u00fang s\u1ed1 n\u00e0o ngh\u0129a l\u00e0 b\u1ea1n \u0111\u00e3 to\u1ea1ch l\u00f4.
\nC\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 hai con = 0,98^27 = 57,957%.
\nX\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c: 2 * x\u00e1c su\u1ea5t tr\u00fang 1 l\u00f4 * x\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4
\nThay s\u1ed1 ta \u0111\u01b0\u1ee3c: 2 * 23,7657% * 0,99^27 = 36,238%.<\/p>\n

C\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 2<\/p>\n

X\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 2 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con
\nThay s\u1ed1: 57,957% + 36,238% = 94,195%.
\nC\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2:
\n100% \u2013 X\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang
\nThay s\u1ed1: 00 \u2013 94,195% = 5,8%<\/p>\n

C\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3<\/a><\/h3>\n

T\u01b0\u01a1ng t\u1ef1 nh\u01b0 c\u00e1ch t\u00ednh x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 2, nh\u01b0ng \u0111\u1ed1i v\u1edbi tr\u01b0\u1eddng h\u1ee3p l\u00f4 xi\u00ean 3 th\u00ec h\u01a1i ph\u1ee9c t\u1ea1p h\u01a1n.
\n\u0110\u1ec3 tr\u00fang l\u00f4 xi\u00ean ba b\u1eaft bu\u1ed9c b\u1ea1n ph\u1ea3i d\u1ef1 \u0111o\u00e1n x\u1ed5 s\u1ed1 tr\u00fang c\u1ea3 3 con. C\u00e1c tr\u01b0\u1eddng h\u1ee3p kh\u00e1c \u0111\u1ec1u to\u1ea1ch l\u00f4. C\u00e1c tr\u01b0\u1eddng h\u1ee3p to\u1ea1ch l\u00f4 xi\u00ean 3:
\n-TH1: D\u1ef1 \u0111o\u00e1n \u0111\u00fang 1 trong 3 s\u1ed1
\n-TH2: D\u1ef1 \u0111o\u00e1n \u0111\u00fang 2 trong 3 s\u1ed1
\n-TH3: Kh\u00f4ng d\u1ef1 \u0111o\u00e1n \u0111\u00fang s\u1ed1 n\u00e0o
\nT\u1eeb \u0111\u00f3 ta c\u00f3 c\u00f4ng th\u1ee9c t\u00ednh x\u00e1c su\u1ea5t kh\u00f4ng tr\u00fang l\u00f4 xi\u00ean 3:
\nX\u00e1c su\u1ea5t kh\u00f4ng v\u1ec1 c\u1ea3 3 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 1 con + x\u00e1c su\u1ea5t ch\u1ec9 v\u1ec1 2 con
\nThay s\u1ed1: 0,97^27 + 3 * 23,7675% * 0,98^27 + 3 * 5,8% * 0,99^27 = 98,527%
\nSuy ra, x\u00e1c su\u1ea5t tr\u00fang l\u00f4 xi\u00ean 3 = 100% \u2013 98,527% = 1,473%.<\/p>\n

K\u1ebft lu\u1eadn<\/h2>\n

Tr\u00ean \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p d\u1ef1 \u0111o\u00e1n soi c\u1ea7u x\u1ed5 s\u1ed1<\/strong><\/a> \u0111\u01b0\u1ee3c cao nh\u00e2n s\u1eed d\u1ee5ng r\u1ea5t ph\u1ed5 bi\u1ebfn. C\u00e1ch t\u00ednh tr\u00ean d\u1ef1a v\u00e0o thu\u1eadt to\u00e1n x\u00e1c su\u1ea5t th\u1ed1ng k\u00ea n\u00ean c\u00f3 \u0111\u1ed9 tin t\u01b0\u1edfng cao. Tuy nhi\u00ean, c\u00e1ch t\u00ednh h\u01a1i ph\u1ee9c t\u1ea1p, anh em n\u00ean ch\u1ecbu kh\u00f3 t\u00ednh to\u00e1n \u0111\u1ec3 ch\u1ed1t c\u1ea7u ch\u00ednh x\u00e1c.
\nCh\u00fac th\u00e0nh c\u00f4ng!<\/p>\n

D\u1ef0 \u0110O\u00c1N XS MI\u1ec0N B\u1eaeC SUPER VIP <\/span><\/h3>\n
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